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2x^2+45x-450=0
a = 2; b = 45; c = -450;
Δ = b2-4ac
Δ = 452-4·2·(-450)
Δ = 5625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5625}=75$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(45)-75}{2*2}=\frac{-120}{4} =-30 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(45)+75}{2*2}=\frac{30}{4} =7+1/2 $
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